Find Tan θ If Sec θ = Square Root Of Ten Divided By Three And Sin θ < 0.
Find Tan Θ If Sec Θ = Square Root Of Ten Divided By Three And Sin Θ < 0.. Find tan (theta) if sec (theta)= sqrt (10)/3 and sin (theta) < 0. Sec θ = (√10)/3 and sin θ < 0.
We know that, cos θ = 1 / sec θ. So if sec = sqrt(7)/2 then cos = 1/sqrt(7)/2 that simplifies to (2*sqrt(7))/7 cos^2= 4/7 4/7 + sin^2=1 sin^2=3/7 sin = sqrt(21)/7 cotagent = cos/sin ((2sqrt7)/7)/((sqrt21)/7 =. Cos θ = 1/[(√10)/3] cos θ = (3/√10) from the trigonometric identity,.
Then Θ Can Be Angle From The Third Quadrant Or Fourth Quadrant.
Find tan (theta) if sec (theta)= sqrt (10)/3 and sin (theta) < 0. Given that sin θ < 0, ⇒ sin θ is negative. Sec(θ) = 3 sec ( θ) = 3 , tan(θ) > 0 tan ( θ) > 0.
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Sec(x) = √37 6 sec ( x) = 37 6. Use the definition of secant to find the known sides of the unit circle right triangle. Cos θ = 1/[(√10)/3] cos θ = (3/√10) from the trigonometric identity,.
Each Student Also Had Some.
If tanθ = 5 2 and θ is an acute angle, find the value of secθ. If sin0, theta must be in quadrant iv where tan<0. Find trig functions using identities sec (theta)=3 , tan (theta)>0.
If Θ Lies In Third Quadrant.
Sec θ = (√10)/3 and sin θ < 0. Three students, javier, sam, and corrine, participated in a fundraiser where people donated a certain amount of money per lap that the student ran. If sec θ = square root of ten divided by three and sin θ < 0.
We Know That, Cos Θ = 1 / Sec Θ.
So if sec = sqrt(7)/2 then cos = 1/sqrt(7)/2 that simplifies to (2*sqrt(7))/7 cos^2= 4/7 4/7 + sin^2=1 sin^2=3/7 sin = sqrt(21)/7 cotagent = cos/sin ((2sqrt7)/7)/((sqrt21)/7 =. The quadrant determines the sign on each of the values. If cos a = 3 2, a is an.
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